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Chapter 3- त्रिकोणमितीय फलन (Trigonometric Functions) Ex-3.3 Interview Questions Answers

Question 1 :

Answer 1 :


Question 2 :

Answer 2 :


Question 3 :

Answer 3 :


Question 4 :

Answer 4 :


Question 5 :
मान ज्ञात कीजिए:
(i) sin (75°)
(ii) tan 15°

Answer 5 :

(i)

(ii)

Question 6 :

Answer 6 :


Question 7 :

Answer 7 :


Question 8 :

Answer 8 :


Question 9 :

Answer 9 :


Question 10 : सिद्धि कीजिए : sin (n + 1)x sin (n + 2)x + cos (n + 1)x cos (n + 2)x = cos x.

Answer 10 :

बायां पक्ष = sin (n + 1)x sin (n + 2) x + cos (n + 1)x cos (n + 2)x
मान लीजिए (n + 2)x = A, (n + 1) x = B
= sin B sin A + cos B cos A
= cos A cos B + sin A sin B
= cos (A – B)
= cos ((n + 2) x – (n + 1) x] [A और B के मान रख कर ]
= cos (nx + 2x – nx – x)
= cos x = दाया पक्ष