RD Chapter 7- Introduction to Euclid-s Geometry Ex-7.1 |
RD Chapter 7- Introduction to Euclid-s Geometry Ex-7.2 |
RD Chapter 7- Introduction to Euclid-s Geometry Ex-7.3 |
RD Chapter 7- Introduction to Euclid-s Geometry Ex-7.4 |
RD Chapter 7- Introduction to Euclid-s Geometry Ex-MCQS |

**Answer
1** :
The equation of x-axis is, y = 0.

**Answer
2** :
The equation of y-axis is, x = 0.

**Answer
3** :
The equation of the line passing through the point (0,4) and parallel to x-axis will be y = 4.

**Answer
4** :
The equation of the line passing through the point (3, 5) and parallel to x-axis will be y = 5.

**Answer
5** :
The equations of the line passing through the point (-3, -7) and parallel to y-axis will be x = -3.

**Answer
6** :
A line parallel to x-axis and passing through the point (-4, 6) will be y = 6.

**Answer
7** :

3x – 2 = 2x + 3

⇒ 3x – 2x = 3 + 2 (By terms formation)

⇒ x = 5

∴ x = 5

Solution on the number line is

**Answer
8** :

2y – 1 = y + 1

⇒ 2y – y = 1 +1

⇒ y = 2

∴ It is a line parallel to x-axis at a distance of 2 units above the x-axis is y = 2.

**Answer
9** :

∵ Point (1, -2) lies on the graph of the equation x – 2y + k = 0

∴ x = 1, y = -2 will satisfy the equation

Now substituting the value of x = 1, y = -2 in it

1-2 (-2) + k = 0

⇒ 1 + 4 + k = 0

⇒ 5+ k = 0 ⇒ k =-5

∴ k = -5

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